Exponential decay/depreciation per time period 't' by a percentage 'r' and an initial amount 'a' is given by the function 'f', where f(t)=a*(1-r)^t. That is:
Example:
In 1967, you could by an Austin Healy 3000 Mark III sports car for $4000.00. Since then, the car has appreciated in value by 6.12% per year.
What function models the value, f, of the car t years after 1967?
Solution: a=4000, r-.0612. Thus,
What was the value of the car in 2004?
Solution: t=37. Thus,
In what year will the car's value appreciate to over $50,000? Explain the process you used to find the answer.
Solution:
Solve 50000=4000*(1.0612)^t
by graphing
y1=50000
y2=4000*(1.0612)^x
and find the x-value of the intersection of y1 and y2.
x=42.5 year
2009.5, or 2010 by rounding up.
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